GetNext()
Gets a new instance of AdviceEnumerator<T> that points to the next item.
Declaration
public AdviceEnumerator<T> GetNext()Returns
| Type | Description |
|---|---|
| AdviceEnumerator<T> | A new AdviceEnumerator<T> that points to the next item. |
Gets a new instance of AdviceEnumerator<T> that points to the next item.
public AdviceEnumerator<T> GetNext()| Type | Description |
|---|---|
| AdviceEnumerator<T> | A new AdviceEnumerator<T> that points to the next item. |