MetalamaAPI documentationAspect APIMetalama.​Framework.​CodeINamed­TypeIs­Subclass­Of
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INamedType.IsSubclassOf Method

IsSubclassOf(INamedType)

Determines whether the type if subclass of the given class or interface.

Declaration
bool IsSubclassOf(INamedType type)
Parameters
Type Name Description
INamedType type
Returns
Type Description
Boolean